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A capacitor of 10 pF is connected to a voltage source of 100 V. If the distance between the capacitor plates is reduced to 50 % while it remains, connected to the 100 V supply. Find the new values of charge, energy stored and potential as well as potential gradient. Which of these quantities increased by reducing the distance and why ? |
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Answer» (i) C = 10 pF (ii) C = 20 pF, distance halved Charge = 1000 p Coul Charge = 2000 p-coul Energy = 1/2 CV2 = 0.05 μ J Energy = 0.10 μ J Potential gradient in the second case will be twice of earlier value |
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