InterviewSolution
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InterviewSolution
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The voltage across a 5microF capacitor change uniformly from 10 to 70V in 5ms. Calculate the change in capacitor charge and charging current. |
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Answer» Given c = 5μF t = 5ms ΔV = 10 to 70V change in capacitor charge Δq = cΔV = 5 x 10-6 (Vf - Vi) = 5 x 10-6 (70 - 10) = 300 x 10-6 Δq = 0.3 mC change in current i = c dv/dt i = 5 x 10-6 x \(\frac{60}{5\times10^{-3}}\) i = 60 x 10-3 i = 60 mA |
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