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A capalitor of capitance C= (2.0 +0.1) MF charged to a voltage V= (20 + 0.2) volt. What will be the charge Q on the capacitor ? UseQ = CV6​

Answer» C = (2.0 + 0.1 ) = 2.1 V= (20+0.1) = 20.1 THEREFORE Q =CV6I.e 2.1× 20.1×6 = 253.26.......... So Q = 253.26


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