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A capalitor of capitance C= (2.0 +0.1) MF charged to a voltage V= (20 + 0.2) volt. What will be the charge Q on the capacitor ? UseQ = CV6​

Answer» <html><body><a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a> = (2.0 + 0.1 ) = 2.1 <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>= (20+0.1) = 20.1 <a href="https://interviewquestions.tuteehub.com/tag/therefore-706901" style="font-weight:bold;" target="_blank" title="Click to know more about THEREFORE">THEREFORE</a> <a href="https://interviewquestions.tuteehub.com/tag/q-609558" style="font-weight:bold;" target="_blank" title="Click to know more about Q">Q</a> =CV6I.e 2.1× 20.1×6 = 253.26.......... So Q = 253.26</body></html>


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