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A capillary of internal radius `4 mm`, is dipped in water. To how much height, will the water rise in the capillary. (`T_(water) = 70 xx 10^(-3) N//m, g = 10 m//sec^(2), rho_(water) 10^(3) kg//m^(3)`, contact angle `theta rarr 0`) |
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Answer» Capillary rise `h = (2T)/(rhoPR)costheta = (2 xx 70 xx 10^(-3))/(10^(3) xx 10 xx 4 xx 10^(-3)) …(1)` `h = 3.5 mm` |
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