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Pressure inside two soap bubble are 1.02 and 1.03 atm . Then ratio of their volumes isA. `8 :27`B. `27:8`C. `(1.02)^(3) :(1.03)^(2)`D. `(1.03)^(3):(1.02)^(2)` |
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Answer» Correct Answer - B ` (V_(1))/(V_(2)) = ((P_(2))/(P_(1)))= ((0.03)/0.02 )^(3)= (3)^(2) : (2)^(3) = 27 : 8 ` |
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