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A capillary tube is radius 0.02 cm is dipped vertically in a beaker containing mercury . The level of mercury in the tube with respect to the mercury level in the beaker will be (Given density of mercury 13.5 g/cc ,Surface tension 540 dyne/cm and the angle of contact `135^(@)` )A. `2.88` cm belowB. `2.88 ` cm aboveC. ` 4.08 `cm belowD. ` 4.08 ` cm above |
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Answer» Correct Answer - A `2T cos theta = h rho gr` ` :. h = (2T cos theta )/(pgr) = (2xx540 xxcos_(1)xx35)/(13.5 xx1000xx0.02)` ` = (-2 xx540 xx sin 45)/(135xx2)` ` = (-540)/(135) xx1/(sqrt(2)) = -2.88 `cm below |
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