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a car accelerated from 10 kilometre per hour to 40 kilometre per hour into minutes how much distance does it cover in this period (assume that the path is straight) |
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Answer» Initial VELOCITY of car (u) = 10km/hr final velocity of car(V) = 40 km/hr Time taken(t) = 1minutes = 1/60hr Acceleration of the car(a) = v - u t = 40 -10 1/60 = 30 × 60 = 1800km/hr² Now, using Equation v² = u²+2as (40)²= (10)²+2×1800×s 1600-100 = 3600s 1500 = 3600s s = 1500 = 5/12km 3600 |
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