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A car at rest accelerate uniformly to a speed of 90 km h in 30 sec. How much distance is covered by the car? |
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Answer» We know, A=change in velocity/time taken=V-u/t Initial velocity(u)= 0 Final velocity(v)=90kmph=25m/s(From KMPH to mps=90×5/18) Time(t)= 30 sec So, 25–0/30=5/6m/s. Mark as Brainlest |
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