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A car battery of emf 12 V and internal resistance 5×10-2 Ω, receives a current of 60 amp, from external source, then potential difference of battery is.(a) 12 V (b) 9 V(c) 15 V(d) 20 V |
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Answer» (c) 15V When cell is changed by an external source, terminal voltage, V = E + Ir V = 12 + 60 × 5 × 10-2 =15. |
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