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A car has initial velocity of 72km/hr. It is accelerated at 2 m/ s^2 . Calculate the final velocity and distance covered after 3 sec . what is the distance covered by a car in 3rd second ?

Answer» <html><body><p>93.6kmph, 69 metres.Explanation:We have <a href="https://interviewquestions.tuteehub.com/tag/u-1435036" style="font-weight:bold;" target="_blank" title="Click to know more about U">U</a> as 72kmph. This is equal to 20 m/s. t= <a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> seconds. To <a href="https://interviewquestions.tuteehub.com/tag/find-11616" style="font-weight:bold;" target="_blank" title="Click to know more about FIND">FIND</a> final velocity, v, use the formulav=u+at=20+2*3= 26 m/s= 93.6 km/hr.To find distance, use formulas= <a href="https://interviewquestions.tuteehub.com/tag/ut-718961" style="font-weight:bold;" target="_blank" title="Click to know more about UT">UT</a> +0.5at^(2).s=20*3 +2*9/269 m</p></body></html>


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