A car increase it's velocity from 36km/hr To 72km/hr in 20 sec find th

1.	A car increase it's velocity from 36km/hr To 72km/hr in 20 sec find the distance travelled by the car during this time
Answer» To FIND : We need to find distance travelled by car. Solution : Initial velocity of car (u) = 36km/hr Final velocity of car (v) = 72km/hr TIME taken = 20 seconds Distance travelled = ? Converting KM/hr to m/s 1km = 1000 m 1hr = 3600sec 36km/hr = 10m/s 72km/hr = = 20m/s As we know that, Acceleration = v - u/t ⇛a = 20 - 10/20 ⇛a = 10/20 ⇛a = 1/2 m/s² By using Newton's second law of motion s = ut + ½at² ›› s = 10 × 20 + 1/2 × 1/2 × 20² ›› s = 200 + 1/4 × 400 ›› s = 200 + 100 ›› s = 300M Hence, Total Distance covered by car = 300m OR in km :- 1km = 1000m ›› 300m into km = 300/1000 Distance travelled = 0.3Km ━━━━━━━━━━━━━━━━━━━━━━━━━

A car increase it's velocity from 36km/hr To 72km/hr in 20 sec find the distance travelled by the car during this time

Answer»

To FIND :

We need to find distance travelled by car.

Solution :

Initial velocity of car (u) = 36km/hr
Final velocity of car (v) = 72km/hr
TIME taken = 20 seconds
Distance travelled = ?

Converting KM/hr to m/s

1km = 1000 m
1hr = 3600sec

36km/hr = 10m/s

72km/hr = = 20m/s

As we know that,

Acceleration = v - u/t

⇛a = 20 - 10/20

⇛a = 10/20

⇛a = 1/2 m/s²

By using Newton's second law of motion

s = ut + ½at²

›› s = 10 × 20 + 1/2 × 1/2 × 20²

›› s = 200 + 1/4 × 400

›› s = 200 + 100

›› s = 300M

Hence,

Total Distance covered by car = 300m

OR in km :-

1km = 1000m

›› 300m into km

= 300/1000

Distance travelled = 0.3Km

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