A car is accelarated at 4m/s² has a velocity of 10 m/s when it cross

1.	A car is accelarated at 4m/s² has a velocity of 10 m/s when it cross a lamp post . The distance travelled by the car in 8th second after crossing the lamp post is
Answer» GIVEN:- $\mathcal{Acceleration = 4m/s}$ $\mathcal{<klux>INITIAL</klux>\:Velocity = 10m/s}$ $\mathcal{Time\:Taken= 8s}$ TO FIND:- The Distance travelled by the car in 8TH SECOND after CROSSING the lamp post. FORMULAE USED:- ${\large{\boxed{\mathbb{S_nth =u +\dfrac{a}{2}(2n-1)}}}}$ Where, S = Distance u = Initial Velocity n = Time a = Acceleration. Now, $\implies\mathcal{S = u + \dfrac{a}{2}(2n-1)}$ $\implies\mathcal{ S = 10 + \dfrac{4}{2}(2(8)-1)}$ $\implies\mathcal{S = 10 + 2 (15)}$ $\implies\mathcal{ S = 40m}$ . Hence, The Distance travelled by car is 40m.