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A car is moving with initial velocity 2m/s and acceleration 4 m/s2.Find the distance travelled by the car in 9 th second

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Question - If a body is moving with an initial velocity of 3m/s and an acceleration of 2m/s, then what will be the distance travelled by the 4th second?

Answer - When t=4

s= ut+ 0.5 X at^2

s= 3 x 4+ 0.5 x 2 x 4^2

s= 12+ 16

s= 28 m

When t=3

s= ut+ 0.5 x at^2

s= 3 x 3+ 0.5 x 2 x 3^2

s= 9+ 9

s= 18 m



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