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A car is moving with initial velocity 2m/s and acceleration 4 m/s2.Find the distance travelled by the car in 9 th second |
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Answer» Question - If a body is moving with an initial velocity of 3m/s and an acceleration of 2m/s, then what will be the distance travelled by the 4th second? Answer - When t=4 s= ut+ 0.5 X at^2 s= 3 x 4+ 0.5 x 2 x 4^2 s= 12+ 16 s= 28 m When t=3 s= ut+ 0.5 x at^2 s= 3 x 3+ 0.5 x 2 x 3^2 s= 9+ 9 s= 18 m |
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