1.

A car moves at a velocity 2.24 `km h^(-1)` in first minute, at 3.60 `km h^(-1)` in the second minute and at 5.18 `km h^(-1)` in the third minute. Calculate the average velocity in od car in this interval of time.

Answer» Displacement in first minute `s_(1)=v_(1)xxt_(1)=2.24xx(1)/(60)km`
Displacement in second minute `s_(2)=v_(2)xxt_(2)=3.60xx(1)/(60)km`
Displacement in third minute `s_(3)=v_(3)xxt_(3)=5.18xx(1)/(60)km`
Total Displacement, `s=s_(1)+s_(2)+s_(3)=(2.24)/(60)+(3.60)/(60)+(5.18)/(60)=(11.02)/(60)km`.
Total time taken, `t=1+1+1=3 "min"=(1)/(20)h`
`therefore "average velocity",=(s)/(t)=(11.02)/(60)xx(20)/(1)=3.67 kmh^(-1)`


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