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A car moves with speed 60 km/h for 1 hour in eastdirection and with same speed for 30 min in southdirection. The displacement of car from initial(position is(1) 60 km(2) 30 3 km(3) 30/5 km(4) 60/2 km |
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Answer» Given: speed = 60km/hrTime (t1)= 1hr , time(t2)=30min= 30/60= 1/2 hr Distance travelled by a car in East direction(s1)= speed× t1 = 60× 1= 60km Distance travelled by a car in south direction(s2)= speed× t1 = 60×1/2= 30 km Displacement from intial position(s)= √(s1)²+(s²)²= √ (60)²+(30)²= √3600+900= √900(4+1)= 30√5 Displacement= 30√5km_____________________________The displacement of car from initial position is 30√5km |
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