A car of mass 1000 kilogram travelling at 32 metre per second dashes i

1.	A car of mass 1000 kilogram travelling at 32 metre per second dashes into a truck of mass 8000 kilogram moving in the same direction with a velocity of 4 metre per second. after the collision the ka bounces back with the velocity of 8 metre per second. what is velocity of that after the collisionanswer is 9 metre per second how ..tell me
Answer» Given : M1 ,MASS of car = 1000kg M2 , mass of TRUCK = 8000 kg U1 , initial velocity of car = 32 m/s U2 , initial velocity of truck = 4 m/s V1 , final velocity of car = 8 m/s To Find : V2 , Final velocity of truck Conservation Of Momentum : $\boxed{\green{m1u1+m2u2=m1v1+m2v2}}$ Solution : (1000 * 32) + (8000 * 4) = (1000 * – 8) + (8000 v2) ∴ 32000 + 32000 = – 8000 + 8000 v2 ∴ 64000 = 8000 (v2 – 1) ∴ v2– 1 = 8 v2 = 9 m/s ☆ *THEREFORE V2 =* 9m/s

A car of mass 1000 kilogram travelling at 32 metre per second dashes into a truck of mass 8000 kilogram moving in the same direction with a velocity of 4 metre per second. after the collision the ka bounces back with the velocity of 8 metre per second. what is velocity of that after the collisionanswer is 9 metre per second how ..tell me

Answer»

Given :

M1 ,MASS of car = 1000kg

M2 , mass of TRUCK = 8000 kg

U1 , initial velocity of car = 32 m/s

U2 , initial velocity of truck = 4 m/s

V1 , final velocity of car = 8 m/s

To Find :

V2 , Final velocity of truck

Conservation Of Momentum :

$\boxed{\green{m1u1+m2u2=m1v1+m2v2}}$

Solution :

(1000 * 32) + (8000 * 4) = (1000 * – 8) + (8000 v2)

∴ 32000 + 32000 = – 8000 + 8000 v2

∴ 64000 = 8000 (v2 – 1)

∴ v2– 1 = 8

v2 = 9 m/s

☆ THEREFORE V2 = 9m/s

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