A car of mass m starts from rest and acquires a velocity along east `upsilon = upsilonhati (upsilon gt 0)` in two seconds Assuming the car moves with uniform acceleration the force exerted on the car is .A. `(mv)/(2)` eastward and is exerted by the car engineB. `(mv)/(2)` eastward and is due to the friction on the tyres exerted by the roadC. more than `(mv)/(2)` eastward exerted due to the engine and overcomes the friction of the roadD. `(mv)/(2)` exerted by the engine

A car of mass m starts from rest and acquires a velocity along east `u

1.	A car of mass m starts from rest and acquires a velocity along east `upsilon = upsilonhati (upsilon gt 0)` in two seconds Assuming the car moves with uniform acceleration the force exerted on the car is .A. `(mv)/(2)` eastward and is exerted by the car engineB. `(mv)/(2)` eastward and is due to the friction on the tyres exerted by the roadC. more than `(mv)/(2)` eastward exerted due to the engine and overcomes the friction of the roadD. `(mv)/(2)` exerted by the engine
Answer» Correct Answer - B Given , mass of the car = m As car starts from rest u = 0 Velocity acquired along east = `v hati` Duration = t = 2s We know that `" " v = u + at` `implies " " vhati = o + a xx 2` `implies " " a = (v)/(2) hati` Force , `" " F = ma = (mv)/(2) hati` Hence , force acting on the car is `(mv)/(2)` towards east . As external force on the system is only friction hence , the force `(mv)/(2)` is by friction . hence force , by engine is internal force .

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