A car of mass m starts from rest and acquires a velocity along east `upsilon = upsilonhati (upsilon gt 0)` in two seconds Assuming the car moves with unifrom acceleration the force exerted on the car is .A. `(mv)/(2)` eastward and is exerted by the car engine.B. `(mv)/(2)` eastward and is due to the friction on the tyres exerted by the road.C. more than `(mv)/(2)` eastward exerted due to the 2 engine and overcomes the friction of the road.D. `(mv)/(2)` exerted by the engine.

A car of mass m starts from rest and acquires a velocity along east `u

1.	A car of mass m starts from rest and acquires a velocity along east `upsilon = upsilonhati (upsilon gt 0)` in two seconds Assuming the car moves with unifrom acceleration the force exerted on the car is .A. `(mv)/(2)` eastward and is exerted by the car engine.B. `(mv)/(2)` eastward and is due to the friction on the tyres exerted by the road.C. more than `(mv)/(2)` eastward exerted due to the 2 engine and overcomes the friction of the road.D. `(mv)/(2)` exerted by the engine.
Answer» Correct Answer - B Here, Mass of the car=m Initial velocity, u=0 (As the car starts from rest) Final velocity `bar(v)=vbar(i)` along east t=2s Using, `v=u+atRightarrow v hati=0+bar(a)xx2 or bar(a)=(v)/(2)hati` Force exerted on the car is `bar(F)=mbar(a)=(mv)/(2) hat(i)=(mv)/(2)"eastward"` This is due to the friction on the tyres exerted by the road.

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