1.

A car running at 10 m/s in the west takes a sharp turn towards north and continues at 10 m/s.If it takes 2 seconds .find the acceleration of the car.​

Answer»

QUESTION:

A car running at 10 m/s in the west takes a sharp turn towards north and CONTINUES at 10 m/s.If it takes 2 seconds .find the acceleration of the car.

Answer:

Acceleration of the car = 5√2 m/s²

Step-by-step-explanations

Given that,

A car running at 10 m/s in the west takes a sharp turn towards north and continues at 10 m/s

Here,

V1 of the car = 10 m/s west

V2 of the car = 10 m/s north

acceleration = change in velocity/time

change in velocity = V2 - V1

= V + (-V1)

so,

here,

ACCORDING TO THE FIGURE

-V1 = 10m/s east

V2 = 10 m/s north

and

angle of VECTORS = 90°

now,

let

V2 - V1 = R

where,

V = 10 m/s each

R² = v² + v² - 2(v)(v) cosθ

putting the values

R² = (10)² + (10)² - 2(10)(10)cos90

R² = 100 + 100 - 200 × 0 [cos90 = 0]

R² = 200

R = √200

R = 10√2

V2 - V1 = 10√2

so,

Change in velocity = 10√2 m/s

now,

also given that

time taken in CHANGING velocity

= 2 seconds

and we know that,

Acceleration =

Change in velocity/time taken

putting the values,

10√2/2

= 5√2 m/s²

so,

Acceleration of the car

= 5√2 m/s²


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