A car starts from rest acquires a velocity of 180 m/s² in 0.05m/s².

1.	A car starts from rest acquires a velocity of 180 m/s² in 0.05m/s². Find the acceleration
Answer» Correct QUESTION : A car starts from rest acquires a velocity of 180 m/s in 0.05 h. Find the acceleration. AnsWer : We're GIVEN that, a car start from the rest i.e initial velocity (u) will be 0 m/s and aquires a velocity of 180 m/s i.e final velocity (v) is 180 m/s and time interval (t) is 0.05 h. We're asked to find the Acceleration (a) of the car. We can solve this question by using two methods/formulas : Acceleration = (Final Velocity - Initial Velocity)/time interval By using FIRST equation of motion :- v = u + at So, you can USE both methods to solve this question. Here, I will use the second method i.e by using first kinematical equation of motion : ↠ v = u + at Here, v = final velocity u = initial velocity a = Acceleration t = time interval Plug in the known values in above given FORMULA: ↠ 180 = 0 + a(0.05 × 3600) ↠ 180 = a(180) ↠ a = 180/180 ↠ a = 1 m/s² ∴ The Acceleration (a) of the car is 1 m/s².

A car starts from rest acquires a velocity of 180 m/s² in 0.05m/s². Find the acceleration

Answer»

A car starts from rest acquires a velocity of 180 m/s in 0.05 h. Find the acceleration.

We're GIVEN that, a car start from the rest i.e initial velocity (u) will be 0 m/s and aquires a velocity of 180 m/s i.e final velocity (v) is 180 m/s and time interval (t) is 0.05 h.
We're asked to find the Acceleration (a) of the car.

We can solve this question by using two methods/formulas :

So, you can USE both methods to solve this question. Here, I will use the second method i.e by using first kinematical equation of motion :

↠ v = u + at

Here,

Plug in the known values in above given FORMULA:

↠ 180 = 0 + a(0.05 × 3600)

↠ 180 = a(180)

↠ a = 180/180

↠ a = 1 m/s²

∴ The Acceleration (a) of the car is 1 m/s².