A car starts from rest and acquire on velocity of 54km/hr in 2min.find

1.	A car starts from rest and acquire on velocity of 54km/hr in 2min.find acceleration.and distance travelled
Answer» ✬ Distance = 900 m ✬ ✬ Acceleration = 0.125 m/s² ✬ Explanation: Given: A car tarted from rest i.e Initial VELOCITY is 0. Final velocity of car is 54 km/hr Time taken is 2 minutes. To Find: What is the ACCELERATION and Distance covered by car ? Formula to be used: v = u + at (for acceleration) s = ut + 1/2at² ( for distance ) Solution: First CHANGE the units in m/s to make units same. ➯ 1 minutes = 60 SECONDS ➯ 2 minutes = 2(60) = 120 seconds. Multiply with 5/18 to change km/h to m/s. ➯ Final velocity = 54(5/18) ➯ v = 15 m/s. Now, put the values on formula. $\implies{\rm }$ v = u + at $\implies{\rm }$ 15 = 0 + a $\times$ 120 $\implies{\rm }$ 15 = 120a $\implies{\rm }$ 15/120 = a $\implies{\rm }$ 0.125 m/s² = a So, the acceleration of car is 0.125 m/s². __________________________ Using second formula for finding distance $\implies{\rm }$ s = ut + 1/2at² $\implies{\rm }$ s = 0 $\times$ 120 + 1/2 $\times$ 0.125 $\times$ 120² $\implies{\rm }$ s = 0.125/2 $\times$ 14400 $\implies{\rm }$ s = 0.125 $\times$ 7200 $\implies{\rm }$ s = 900 m Hence, the distance covered by car is 900 m.

A car starts from rest and acquire on velocity of 54km/hr in 2min.find acceleration.and distance travelled

Answer»

✬ Distance = 900 m ✬

✬ Acceleration = 0.125 m/s² ✬

Explanation:

Given:

To Find:

Formula to be used:

Solution: First CHANGE the units in m/s to make units same.

➯ 1 minutes = 60 SECONDS

➯ 2 minutes = 2(60) = 120 seconds.

Multiply with 5/18 to change km/h to m/s.

➯ Final velocity = 54(5/18)

➯ v = 15 m/s.

Now, put the values on formula.

$\implies{\rm }$ v = u + at

$\implies{\rm }$ 15 = 0 + a $\times$ 120

$\implies{\rm }$ 15 = 120a

$\implies{\rm }$ 15/120 = a

$\implies{\rm }$ 0.125 m/s² = a

So, the acceleration of car is 0.125 m/s².

Using second formula for finding distance

$\implies{\rm }$ s = ut + 1/2at²

$\implies{\rm }$ s = 0 $\times$ 120 + 1/2 $\times$ 0.125 $\times$ 120²

$\implies{\rm }$ s = 0.125/2 $\times$ 14400

$\implies{\rm }$ s = 0.125 $\times$ 7200

$\implies{\rm }$ s = 900 m

Hence, the distance covered by car is 900 m.