Saved Bookmarks
| 1. |
A car starts from rest and moves with constant acceleration the ratio of distance covered by |
|
Answer» Answer: Distance covered in n SECONDS is simply calculated by 2ND equation of motion….. S(n)= UN + 1/2(a) (n^2) Where u=0 becoz object is at rest initially so it BECOME s(n)= 1/2(a)(n^2) #Distance covered in nth SECOND is define as distance covered from (n) to (n+1) second which comes as s(nth)= (a/2)×(2n+1). Hence ratio will comes as (2n+1)/(n^2). |
|