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A car starts from rest and moves with uniform acceleration `a`, At the same instant from the same point a bike crosses with a uniform velocity `u`. When and there will they meet ? What is the velocity of car with respect to the bike at the time of meeting? |
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Answer» `underset("car")(s)=(1)/(2)at^(2)to(1),underset("bike")(s)=ut to(2)` if they meet at the same point `underset("car")(s)=underset("bike")(s)` `(1)/(2)at^(2)=ut impliest=(2u)/(3)` ltbr `S_("bike")=ut=u(2u)/(a)=(2u^(2))/(a)` `V_("car")=at=2u` `V_("car")` w.r.t. bike at the time of meeting, `|vec V_(cb)|=|vec(V)_("car")-vec(V)_("bike")|=2u-u=u` |
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