1.

A car travelling at a speed 54km/his brought to rest in abs Find thedistance travelled by the car beforecomingrest

Answer»

Initial speed = 54Km/h = 54×5/18 = 15m/sfinial speed = 0time = 90sv = u + at0 = 15 + 90aa = -1/6let distance = sv² = u² + 2as0 = 15² - 2×s/6s = 225×3s = 675 m



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