1.

A car travels a distance 50 km with a velocity 25 km h^(-1) and then 60 km with a velocity 20 km h^(-1) in the same direction. Calculate : (i) the total time of journey and (ii) the average velocity of the car.

Answer»

Solution :Given `S_(1)= 50 ` km `v_(1)` 25 km `H^(-1)`.
`S_(2)= 60 ` km , `V_(2)= 20` km `h^(-1)` .
(i) Time of journey t `= ("Distance S")/("velocity v")`
`:. T_(1) = (S_(1))/(v_(1))= (50 km)/(25 km h^(-1))= 2 `h
`t_(2)= (S_(2))/(v_(2))= (60 km)/(20 km h^(-1))=3 `h
Total time of journey t = `t_(1)+t_(2)`= 2h +3 h = 5 h
(II) Total distance travelled `S=S_(1)+S_(2)`
= 50 km + 60 km = 110 km
Average velocity = `("Total distance travelled S")/("Total time of journey t ") `
`= (110km )/(5 h)` = 22 km `h^(-1)`.


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