A car travels half of the distance with constant velocity 30 m/s and t

1.	A car travels half of the distance with constant velocity 30 m/s and the other half with constant velocity 50m/s. find the average speed of the car
Answer» Given : ➳ A car travels first HALF of the total distance at a speed of 30m/s and SECOND half of the total distance at a speed of 50m/s. To Find : ➛ Average speed of car. SoluTion : ⇒ Average speed is defined as the RATIO of total distance travelled to the total TIME taken. It is a scalar quantity having only magnitude. ⇒ SI unit : m/s ✭ When body covers first half of the total distance at a speed of $\tt{v_1}$ and second half of the total distance at a speed of $\tt{v_2}$ , then average speed of body is given by $\longrightarrow\tt\:v_{av}=\dfrac{2v_1v_2}{v_1+v_2}\\ \\ \longrightarrow\tt\:v_{av}=\dfrac{2(30)(50)}{30+50}\\ \\ \longrightarrow\tt\:v_{av}=\dfrac{3000}{80}\\ \\ \longrightarrow\underline{\boxed{\tt{v_{av}=37.5\:ms^{-1}}}}$

A car travels half of the distance with constant velocity 30 m/s and the other half with constant velocity 50m/s. find the average speed of the car

Answer»

Given :

➳ A car travels first HALF of the total distance at a speed of 30m/s and SECOND half of the total distance at a speed of 50m/s.

To Find :

➛ Average speed of car.

SoluTion :

⇒ Average speed is defined as the RATIO of total distance travelled to the total TIME taken. It is a scalar quantity having only magnitude.

⇒ SI unit : m/s

✭ When body covers first half of the total distance at a speed of $\tt{v_1}$ and second half of the total distance at a speed of $\tt{v_2}$ , then average speed of body is given by

$\longrightarrow\tt\:v_{av}=\dfrac{2v_1v_2}{v_1+v_2}\\ \\ \longrightarrow\tt\:v_{av}=\dfrac{2(30)(50)}{30+50}\\ \\ \longrightarrow\tt\:v_{av}=\dfrac{3000}{80}\\ \\ \longrightarrow\underline{\boxed{\tt{v_{av}=37.5\:ms^{-1}}}}$

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