1.

A Carnot cycle has an efficiency of `40%` . Its low temperature resrvoir is at `7^(@)C` . What is the temperature of source ?

Answer» Correct Answer - `193.66^(@)C`
`eta= (T_(2) - T_(1))/(T_(2))`
`0.4 = (T_(2)- 280)/(T_(2))`
`T_(2)= 466.67 K = 193.66 ^(@)`


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