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A carnot engine absorbs `500J` of heat from a reservoir at `227^(@)C` and rejects of seek (ii) efficiency of engine (iii) amount of useful work done per cycle. |
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Answer» Here, `Q_(1)=500J` `T_(1)= 227^(@)C=227+273= 500K` `Q_(2)= 300J, T_(2)=?, eta=?, W=?` As `(T_(2))/(T_(1))= (Q_(2))/(Q_(1))= (300)/(500)`, `T_(2)= 6/(10)T_(1)= 6/(10)xx500= 300K` `=(300-273)^(@)C= -27^(@)C` `eta=1 - (T_(2))/(T_(1))=1 - (6)/(10)= 4/(10)= 40%` `W=Q_(1)-Q_(2)= 500-300= 200J` |
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