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A carnot engine operates between temperatures `T` and `400K(Tgt400K)`. If efficiency of engine is `25%`, the temperature `T` is :A. `400 K`B. `500 K`C. `533.3 K`D. `600 K` |
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Answer» Correct Answer - C `eta_(("efficiency")) =(T_(2)-T_(1))/(T_(2))` or `0.25=(T-400)/T` `:. T=533.3 K` |
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