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A Carnot engine, whose efficiency is `40%`, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency `60%`. Then, the intake temperature for the same exhaust (sink) temperature must be:A. efficiency of carnot engine cannot be made larger than `50%`B. `1200K`C. `750K`D. `600 K` |
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Answer» Correct Answer - C Here, `eta_(1)= 40%, T_(1)= 500K, T_(2)= T` `eta_(2)= 60%, T_(1)=?, T_(2)=T` From `eta= 1-(T_(2))/(T_(1))` `(40)/(100)=1 -T/(500), T= 300K` `(60)/(100)= 1 -(300)/(T_(1)), T_(1)= 750 K` |
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