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InterviewSolution
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A Carnot engine, whose efficiency is `40%`, takes in heat from a source maintained at a temperature of 500K. It is desired to have an engine of efficiency `60%`. Then, the intake temperature for the same exhaust (sink) temperature must be:A. 1200KB. 750 KC. 600 KD. 800 K |
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Answer» Correct Answer - B Efficiency of carnot engien `eta=1-(T_(2))/(T_(1))` where `T_(1)` is the temperature of the source and `T_(2)` is the temperature of the sink For the `1^(st)` case `eta=40%,T_(1)=500K` `therefore(40)/(100)=1-(T_(2))/(500)` `(T_(2))/(500)=1-(40)/(100)=(3)/(5)` `T_(2)=(3)/(5)xx500=300 K` For the `2^(nd)` case `eta=60%,T_(2)=300 K` `therefore (60)/(100)=1-(300)/(T_(1))` `(300)/(T_(1))=1-(60)/(100)=(2)/(5)` `t_(1)=(5)/(2)xx300=750 K` |
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