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A ceiling fan having M.I.2kgm² attains max.frequency of 60r.p.m.in2 second calculate it's power rating |
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Answer» Power RATING of fan = 40 WExplanation:Moment of Inertia I = 2 kg m²As fan starts from rest and attains max frequencyInitial angular velo ω₀ = 0Final angular velo ω = 2πN/60 = 2π x 60/60 = 2π rad /sAngular accln α = (ω - ω₀) / t = 2π/2 = π rad/s²Maximum TORQUE τ = I α = 2 x π = 2π N mPower rating = Pmax = Torque x angular velo = τω = 2π x 2π = 4 x π² = 4 x 3.14 x 3.14 = 39.43 = 40 W |
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