A cell `Cu|Cu^(++)||Ag^(+)|Ag` initially contains `2MAg^(+)` and `2MCu^(++)` ions in 1 L electrolyte. The change in cell potential after the passage of 10 amp. Curret for 4825 sec is:A. `-0.00738V`B. `-1.00738V`C. `-0.0038V`D. none

A cell `Cu|Cu^(++)||Ag^(+)|Ag` initially contains `2MAg^(+)` and `2MCu

1.	A cell `Cu\|Cu^(++)\|\|Ag^(+)\|Ag` initially contains `2MAg^(+)` and `2MCu^(++)` ions in 1 L electrolyte. The change in cell potential after the passage of 10 amp. Curret for 4825 sec is:A. `-0.00738V`B. `-1.00738V`C. `-0.0038V`D. none
Answer» Correct Answer - A `Q=10xx4825=48250C` no. of faraday `=(48250)/(96500)=0.5` `Ag+undersetunderset(2-0.25)(2.00)((1)/(2)Cu^(++))toundersetunderset(2+0.50)(2.00)(Ag^(+))+(1)/(2)Cu` `E_(cell)=E_(cell)^(@)-(0.0591)/(1)log(([Ag^(+)])/([Cu^(++)]^(1//2)))` `E_(1)=E_(cell)^(@)-(0.0591)/(1)log((2.00)/((2.00)^(1/2)))` `E_(2)=E_(cell)^(@)-(0.0591)/(1)log((2.50)/((1.75)^(1//2)))` `triangleE=E_(2)-E_(1)=(0.0591)/(1)[logsqrt(2)-log((2.50)/(sqrt(1.75)))]=(0.0591)/(1)[log1.41-log1.88]` `=(0.0591)/(1)[0.1492-0.2742]=-(0.0591)/(1)xx0.125=-0.00738V`.

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A cell `Cu|Cu^(++)||Ag^(+)|Ag` initially contains `2MAg^(+)` and `2MCu^(++)` ions in 1 L electrolyte. The change in cell potential after the passage of 10 amp. Curret for 4825 sec is:A. `-0.00738V`B. `-1.00738V`C. `-0.0038V`D. none

A cell `Cu|Cu^(++)||Ag^(+)|Ag` initially contains `2MAg^(+)` and `2MCu^(++)` ions in 1 L electrolyte. The change in cell potential after the passage of 10 amp. Curret for 4825 sec is:A. `-0.00738V`B. `-1.00738V`C. `-0.0038V`D. none

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