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the standard reduction potenital of a silver chloride electrode is 0.2 V and that of a silver electrode is 0.79 V. The maximum amount of AgCl that can dissolve in `10^(6)`L of a 0.1 M `AgNO_(3)` solution is:A. 0.5 mmolB. 1.0 mmolC. 2.0 mmolD. 2.5 mmol |
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Answer» Correct Answer - B `AgCl+e^(-)toAgtoCl^(-)" "E^(@)=0.2V` `underline(AgtoAg^(+)+e^(-)" "E^(@)=-0.79V` `AgCloverset(e^(-))toAg^(+)+Cl^(-)" "E^(@)=-0.59V` `E^(@)=(0.059)/(n)logKimplies-0.59=(0.059)/(1)logK_(SP)impliesK_(SP)=10^(-10)` Now solubility of `AgCl` in 0.1 M `AgNO_(3)` `S(S+0.1)=10^(-10)impliesS=10^(-9)mol//L` Hence 1 mole dissolves in `10^(9)L` L solution. Hence in `10^(6)L` L amount that dissoves in 1 m mol. |
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