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A cell has an emf of 1.5 V. When short circuited, it gives a current of 3A. The internal resistance of the cell is.(a) 0.5 Ω (b) 2.0 Ω (c) 4.5 Ω (d) \(\frac{1}{4.5}\) Ω |
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Answer» (a) 0.5 Ω r =\(\frac{ξ}{I}\)= \(\frac{1.5}{3}\) = 0.5 Ω. |
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