1.

A certain electric motor produced `16kJ` of energy each second as mechanical work and lost `3kJ` as heat to the surroundings. What is the change in the internal energy of the motor and its power supply each second?

Answer» Energy is lost form the system as work, thus `W` is negative.
`:. W =- 16kJ`
Enegry is lost as heat, so `q =- 3kJ`
Therefore, by the first law of thermodnamics,
`DeltaU = q +w =- 3 - 16 - 19kJ`


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