1.

A certain fan is capable of using 4800J of electrical energy each minute,converting 4000J of it into kinetic energy of the fan .what is the efficiency of this fan?​

Answer»

Answer:

  • Hence, the efficiency of the FAN is 120%

Explanation:

Given that:

  • A certain fan is capable of USING 4800J of electrical energy each minute,converting 4000J of it into kinetic energy of the fan.

To FIND:

  • the efficiency of this fan?

Solution:

We KNOW that

Efficiency=Output Energy/Input Energy ×100%

= ( \frac{4800}{4000} ) \times 100\% \\  = 1.2 \\  = 1.2 \times 100 \\  = 120\% \\

Hence, the efficiency of the fan is 120% Ans.

Hope it's help you.



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