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A certain force acts on a body of mass 10 kg and changes its velocity from 2m/sec to 5m/sec calculate the work done by the force |
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Answer» Answer: W = ∆KEW = 1/2m (Vf^2 - vi^2)w = 1/2 × 10 (25-4) W = 105Joule. Thanks for Reading |
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