1.

A certain force acts on a body of mass 10 kg and changes its velocity from 2m/sec to 5m/sec calculate the work done by the force

Answer»

Answer:

WORK DONE by all Forces = ∆KE

W = ∆KE

W = 1/2m (Vf^2 - vi^2)

w = 1/2 × 10 (25-4)

W = 105Joule

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