1.

A Certain Quantity Of 40% Solution Is Replaced With 25% Solution Such That The New Concentration Is 35%. What Is The Fraction Of The Solution That Was Replaced?

Answer»

Consider a solution = 1 LTR

X is the certain QUANTITY which has to be REPLACED

Now,

40%of (1-x)+(25%of x)=35/100 

=> 40/100 * (1-x) + 25x/100 = 35/100 

=> 40/100 - 40x/100 + 25x/100 = 35/100 

=> 15x/100 = 5/100 

=> x = 1/3.

Consider a solution = 1 ltr

X is the certain quantity which has to be replaced

Now,

40%of (1-x)+(25%of x)=35/100 

=> 40/100 * (1-x) + 25x/100 = 35/100 

=> 40/100 - 40x/100 + 25x/100 = 35/100 

=> 15x/100 = 5/100 

=> x = 1/3.


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