1.

A change in the free energy of a system at constant temperature and pressure will be: `Delta_(sys)G = Delta_(sys)H -T Delta_(sys)S` At constant temperature and pressure `Delta_(sys) G lt 0` (spontaneous) `Delta_(sys)G = 0` (equilibrium) `Delta_(sys)G gt 0` (non-spontaneous) If both `DeltaH` and `Deltas` are negative, the reaction will be spontaneousA. At high temperatureB. At all temperaturesC. At low temperatureD. At high pressure

Answer» `DeltaC = DeltaH - T Deltas`


Discussion

No Comment Found

Related InterviewSolutions