1.

A charge q is placed at the centre of the line joining twoequal charges Q. The system of the three charges wil be inequilibrium. if q is equal to

Answer»

Let two equal charges Q placed at point A and B joining line segment. Let length of line segment is x and charge q is placed at centre.

Then distance of charge q from point A and B is x/2

Force on the charge at B due to the charge at A is,

F1 = kQ2^2 /x^2

Force on the charge at B due to the charge q is,

F2 = kQq/(x/2)^2

For the system to be in equilibrium,

F1 + F2 = 0

=> kQ^2/x^2 + kQq/(x/2)^2 = 0

=> q = -Q/4



Discussion

No Comment Found

Related InterviewSolutions