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A charge q is placed at the centre of the line joining twoequal charges Q. The system of the three charges wil be inequilibrium. if q is equal to |
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Answer» Let two equal charges Q placed at point A and B joining line segment. Let length of line segment is x and charge q is placed at centre. Then distance of charge q from point A and B is x/2 Force on the charge at B due to the charge at A is, F1 = kQ2^2 /x^2 Force on the charge at B due to the charge q is, F2 = kQq/(x/2)^2 For the system to be in equilibrium, F1 + F2 = 0 => kQ^2/x^2 + kQq/(x/2)^2 = 0 => q = -Q/4 |
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