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A charge q moves with a velocity Vinto magnetic field 'B' perpendicularly,then the force exerted on it is:A)qVB cos 90°B)qVB tan 90°C)qVB cot 90°D)qVB |
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Answer» The EXPRESSION for force EXPERIENCED by a CHARGE is...... Here .... theta = 90° Therefore....sin theta = 1 ....so....... F = qvB... |
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