1.

A charge q moves with a velocity Vinto magnetic field 'B' perpendicularly,then the force exerted on it is:A)qVB cos 90°B)qVB tan 90°C)qVB cot 90°D)qVB​

Answer»

The EXPRESSION for force EXPERIENCED by a CHARGE is......

F = qvB sin THETA

Here .... theta = 90°

Therefore....sin theta = 1

....so....... F = qvB...



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