A charged particle is projected in a magnetic field B=(3i+4j)*10^-2.Th

1.	A charged particle is projected in a magnetic field B=(3i+4j)*10^-2.The acceleration of the particle is found to be a=(-8/3i+yj)m/s2 . Find the value of y.
Answer» Answer: 2 Explanation: F = Q V X B So, ACCELERATION will be PERPENDICULAR to magnetic field . So, B.a =0 3*(-8/3) +4y = 0 4y = 8 y = 2

A charged particle is projected in a magnetic field B=(3i+4j)*10^-2.The acceleration of the particle is found to be a=(-8/3i+yj)m/s2 . Find the value of y.

Answer»

Answer:

Explanation:

F = Q V X B

So, ACCELERATION will be PERPENDICULAR to magnetic field .

So, B.a =0

3*(-8/3) +4y = 0

4y = 8

y = 2

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A charged particle is projected in a magnetic field B=(3i+4j)*10^-2.The acceleration of the particle is found to be a=(-8/3i+yj)m/s2 . Find the value of y.​

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A charged particle is projected in a magnetic field B=(3i+4j)*10^-2.The acceleration of the particle is found to be a=(-8/3i+yj)m/s2 . Find the value of y.