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A chemist was performing an experiment to study the effect of varying voltage on the velocity and de Broglie wavelength of the electrons. In first experiment, the electron was accelerated through a potential difference of 1kV and in second experiment, it was accelerated through a potential difference of 2kV. The wavelength of de Broglie waves associated with electron is given by: `lamda=(h)/(sqrt(2qVm))` where, V is the voltage through which an electron is accelerated. Putting the values of h, m and q we get: `lamda=(12.3)/(sqrt(V))`Ã… Q. The velocity of electron will be:A. same in bothB. 1.4 times in second experiment than in first experimentC. double in second experiment than in first experimentD. four tiems in the second case than in first case. |
| Answer» Correct Answer - b | |