

InterviewSolution
Saved Bookmarks
1. |
If the threshold wavelength `(lambda_(0))` for ejection of electron from metal is `350 nm ` then work function for the photoelectric emission isA. `1.2 xx 10^-18 J`B. `1.2 xx 10^-20 J`C. `6 xx 10^-19 J`D. `6 xx 10^-12 J` |
Answer» Correct Answer - C ( c) `W = h ( C)/(lamda_0)` :. `W = (6.6 xx 10^-34 xx 3 xx 10^8)/(330 xx 10^-9)` =`(6.6 xx 3 xx 10^-18)/(33)` =`0.6 xx 10^-18` =`6 xx 10^-19 J`. |
|