1.

If the threshold wavelength `(lambda_(0))` for ejection of electron from metal is `350 nm ` then work function for the photoelectric emission isA. `1.2 xx 10^-18 J`B. `1.2 xx 10^-20 J`C. `6 xx 10^-19 J`D. `6 xx 10^-12 J`

Answer» Correct Answer - C
( c) `W = h ( C)/(lamda_0)`
:. `W = (6.6 xx 10^-34 xx 3 xx 10^8)/(330 xx 10^-9)`
=`(6.6 xx 3 xx 10^-18)/(33)`
=`0.6 xx 10^-18`
=`6 xx 10^-19 J`.


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