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The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [`a_0` is Bohr radius] :A. `(h^(2))/(4 pi^(2) ma_(0)^(2))`B. `(h^(2))/(16 pi^(2) ma_(0)^(2))`C. `(h^(2))/(32 pi^(2) ma_(0)^(2))`D. `(h^(2))/(64 pi^(2) ma_(0)^(2))` |
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Answer» Correct Answer - C |
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