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If `I_(0)` is the threshold wavelength for photoelectric emission, 1 the wavelength of light falling on the surface of a metal and m is the mass of the electron, then the velocity of ejected electron is given byA. `[(2h)/(m)(lambda - lambda)]^(1//2)`B. `[(2hc)/(m)(lambda_(0)-lambda)]^(1//2)`C. `[(2hc)/(m){(lambda_(0)-lambda)/(lambda lambda_(0))}]^(1//2)`D. `[(2hc)/(m){(1)(lambda_(0))-(1)/(lambda)}]^(1//2)` |
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Answer» Correct Answer - C `(hc)/(lambda) = h(c)/(lambda_(0)) +(1)/(2)mv^(2), hc[(1)/(lambda)-(1)/(lambda_(0))] = (1)/(2)mv^(2)` `V = ((2hc)/(m)[(lambda_(0)-lambda)/(lambda_(0)lambda)])^(½)` |
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