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A chord of a circle of radius 10 cm subtends a right angle at the centre. Find the area of the corresponding : (i) minor segment (ii) major sector. |
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Answer» 1) area(minor segment)=area(sectorOAB)-area(triangleOAB) =`theta/360pir^2-1/2OA*ob` =`90/360*22/7*100^2-1/2100^2` =28.25 `cm^2` 2) area(major segment)=`theta/360*3.14*100^2`=`270/360*3.14*100^2`=235.5 `cm^2` |
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