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In fig. O is the center of a circle such that diameter AB=13cm and AC= 12 cm. BC is joined. Find the area of the shaded region. |
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Answer» Here, `BC = sqrt(13^2-12^2) = 5cm` Radius of circle `(r) = (AB)/2 = 13/2 = 6.5cm` `:.` Area of shaded region `(A_s) = ` Area of semi circle - Area of `Delta ABC` `=>A_s = pi/2(6.5)^2-(1/2**12**5)` `=>A_s = 3.14/2(6.5)^2-30 = 66.3325-30 = 36.333cm^2` |
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