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A chord of a circle of radius 15 cm subtends an angle of `60o`at the centre. Find the areas of the corresponding minor and major segments of the circle. |
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Answer» area(minor segment)=area(sector OAB)-area(triangleOAB) =`theta/360^0pir^2-sqrt3/4r^2` =`60/360*pi 15^2-sqrt3/4 15^2` =20.4375 `cm^2` area(major segment)=`pir^2-20.4375` =`3.14*225-20.4375` =686.0625 `cm^2` |
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